Thread: Math for Marines

<div class='quotetop'>QUOTE (Migflanker @ Jul 8 2009, 09:55 AM) <{POST_SNAPBACK}></div>

Ramper Math

If 3 rampers can eat 3 steaks in 3 days, how many steaks can 6 rampers eat in 6 days?

*think carefully* [/b]

<div class='quotetop'>QUOTE (spongebue @ Jul 23 2009, 07:56 AM) <{POST_SNAPBACK}></div>

I was a math/computer science major (now just CS). The answer is 12 [/b]

Brian you obviously paid attention in class, 12 is correct.

If 3 rampers can eat 3 steaks in 3 days, then 6 rampers can eat 6 steaks in 3 days. So - in 6 days the 6 rampers will be able to eat twice as many steaks as 6, which (even us non-math majors know) is 12.

<div class='quotetop'>QUOTE (Migflanker @ Jul 23 2009, 10:20 AM) <{POST_SNAPBACK}></div>

Brian you obviously paid attention in class, 12 is correct.

If 3 rampers can eat 3 steaks in 3 days, then 6 rampers can eat 6 steaks in 3 days. So - in 6 days the 6 rampers will be able to eat twice as many steaks as 6, which (even us non-math majors know) is 12.[/b]

My method is a bit different. Focusing only on the 3 rampers / 3 steaks / 3 days, that leaves 1 steak per day for 3 rampers, or 1/3 of a steak per ramper per day. At that same rate, if you have 6 rampers, you need 2 steaks per day. That times 6 days = 12 steaks.

And yet, when I had to drop Calc II and it was only going to get harder from there (to tell the truth, I was expecting a C or possibly B in Calc I, but did well on the final exam and I think the prof upped my final grade) I decided to transfer schools to get out of the math (I was mostly there for the computer science, anyway).